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4y = -3x + 2
Tegak lurus -> m1 x m2 = -1
m1 = -3
m2 = 1/3
Persamaan garis lurus --> y - y1 = m(x - x1)
y1 = 1, x1 = -4, m = 1/3
y - 1 = 1/3 (x - (-4))
y - 1 = 1/3 x + 4
y = 1/3 x + 4 +1
Persamaan garis lurus yang dimaksud = y = 1/3 x + 5
~maaf kalo salah, saya masi pemula, masi smp :)
a = 3, b = 4
gradien tgak lurus :
m = b/a = 4/3
maka,
pers.grs.melalui ttk.(-4,1) dan m = 4/3 :
y-y1 = m.(x-x1)
y-1 = 4/3 . (x-(-4))
y-1 = 4/3 . (x+4)
kdua ruas dikali dg 3, didapat :
3.(y-1) = 4.(x+4)
3y-3 = 4x+16
4x-3y+16+3 = 0
4x-3y+19 = 0