September 2018 1 29 Report

Te: Potega o wykladniku wymiernym.

a) 49\frac{1}{2}=\sqrt49=7

b) 125\frac{1}{3}=\sqrt[3]{125}=5

2. Oblicz

a) 81\frac{1}{2}

b) 100\frac{1}{2}

c) (\frac{1}{64}) do potegi \frac{1}{2}

d) (\frac{1}{121}) do potegi \frac{1}{2}

e) 169\frac{1}{2}

f) 441\frac{1}{2}

3)Oblicz

a) 8\frac{1}{3}

b) 27\frac{1}{3}

c) 81\frac{1}{4}

d) 64\frac{1}{6}

e) 256\frac{1}{4}

f) 1024\frac{1}{10}

4) Oblicz:

a) 9 do potegi \frac{3}{2}

b) 125 do potegi \frac{2}{3}

c) 16 do potegi \frac{3}{4}

d) 8 do potegi -\frac{4}{3}

e) 27 do potegi -\frac{2}{3}

f) 25 do potegi -\frac{1}{2}

g) 3^3x27 do -\frac{4}{3}potegi

h) 2^2x8\frac{2}{3}

i) 5^3x125 do potegi -\frac{1}{3}

j) 10 000^0^,^2^5

k) 81^-^0^,^5

l) 144^-^0^,^5

Proszę O POMOC!


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