Szybkie i poprawne rozwiązania się liczą !!! Zadanie 2 i 4 są w załączniku !!!
z.2
a) 6^( 1 - p(2)) * 6^(p(2) + 1) = 6^(1 -p(2) +p(2) + 1) = 6^2 = 36
b)
5^(pi + 3) : 5^pi = 5^(pi + 3 - pi ) = 5^3 = 125
c)
2^(3p(5)+5) * 8^( - p(5)) = 2^(3 p(5) +5) * (2^3)^(- p(5)) =
= 2^(3 p(5) + 5) * 2 ^( - 3p(5)) = 2 ^(3p(5) + 5 - 3 p(5)) = 2^5 = 32
d)
4^(p(3) + 2) : 2^(2p(3)) = (2^2)^(p(3) + 2) : 2^(2p(3)) =
= 2^(2p(3) + 4) : 2^(2p(3)) = 2^( 2 p(3) + 4 - 2p(3)) = 2^4 = 16
e)
6^p(3) * 3^(1 - p(3)) *2^(2- p(3)) = 3^p(3) * 2^p(3) * 3^(1 -p(3)) * 2^(2 - p(3)) =
= 3^p(3)* 3^(1 - p(3)) * 2^p(3) * 2^(2 - p(3)) =
= 3^( p(3) + 1 - p(3)) * 2 ^(p(3) + 2 - p(3)) = 3^1 * 2^2 = 3*4 =12
f)
2^(2 pi + 6) * 9 ^(0,5 pi) : 12^pi = 2^(2 pi + 6) *3^pi : 4^pi *3^pi =
= 2^( 2 pi + 6) : 2^(2pi) = 2^(2pi + 6 - 2 pi) = 2^6 = 64
===================================================
z.4
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
z.2
a) 6^( 1 - p(2)) * 6^(p(2) + 1) = 6^(1 -p(2) +p(2) + 1) = 6^2 = 36
b)
5^(pi + 3) : 5^pi = 5^(pi + 3 - pi ) = 5^3 = 125
c)
2^(3p(5)+5) * 8^( - p(5)) = 2^(3 p(5) +5) * (2^3)^(- p(5)) =
= 2^(3 p(5) + 5) * 2 ^( - 3p(5)) = 2 ^(3p(5) + 5 - 3 p(5)) = 2^5 = 32
d)
4^(p(3) + 2) : 2^(2p(3)) = (2^2)^(p(3) + 2) : 2^(2p(3)) =
= 2^(2p(3) + 4) : 2^(2p(3)) = 2^( 2 p(3) + 4 - 2p(3)) = 2^4 = 16
e)
6^p(3) * 3^(1 - p(3)) *2^(2- p(3)) = 3^p(3) * 2^p(3) * 3^(1 -p(3)) * 2^(2 - p(3)) =
= 3^p(3)* 3^(1 - p(3)) * 2^p(3) * 2^(2 - p(3)) =
= 3^( p(3) + 1 - p(3)) * 2 ^(p(3) + 2 - p(3)) = 3^1 * 2^2 = 3*4 =12
f)
2^(2 pi + 6) * 9 ^(0,5 pi) : 12^pi = 2^(2 pi + 6) *3^pi : 4^pi *3^pi =
= 2^( 2 pi + 6) : 2^(2pi) = 2^(2pi + 6 - 2 pi) = 2^6 = 64
===================================================
z.4