Szeiścian o krawędzi 8cm rozcięto na dwa graniastosłupy trójkątne. Oszacuj czy arkusz papieru o wymi.... Question from @Dagusia97s

October 2018 1 13 Report

Szeiścian o krawędzi 8cm rozcięto na dwa graniastosłupy trójkątne. Oszacuj czy arkusz papieru o wymiarach 20cm x 30cm wystarczy na oklejenie powierzchni obu otrzymanych graniastosłupów.

anahi96

Wysokość podstawy

h²+(4√2)²= 8²

h²+32= 64

h²= 32

h= 4√2

Pole powierzchni graniastosłupa trójkątnego

P= 2*8*8+ 2* (8√2*4√2):2+ 8*8√2= 128+64+64√2= 172+64√2 (cm²)

Pole dwóch takich graniastosłupów to 344+128√2 (cm²)

20*30=600 (cm²)

√2≈ 1,4

344+128√2≈ 344+179,2= 523,2 (cm²)

600> 523,2

Odp: Wystarczy papieru.

Liczę na naj :)

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