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Verified answer
Integral Substitusi.∫ (x² - 1)⁶ x dx
u = x² - 1
du / dx = 2x
= ∫ xu⁶ du / (2x)
= 1/2 ∫ u⁶ du
= 1/2 (1/7 u⁷) + C
= 1/14 (x² - 1)⁷ + C