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a^2= 2500 - 1600
a^2 = 900
a = √900
a= 30
H : hipotenusa
C1 : primer cateto
C2 : segundo cateto
Solución:
Usas teorema de pitágoras.
(H)² = (C1)² + (C2)²
(50 u)² = (40 u)² + (C2)²
2500 u² = 1600 u² + (C2)²
2500 u² - 1600 u² = (C2)²
900 u² = (C2)²
√(900 u²) = C2
30 u = C2 ---->>> respuesta
RTA: El segundo cateto mide 30 u.