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liczba II 10b+a
10a+b+10b+a=99
11(a+b)=11•9
a+b=9
10a+b=27+10b+a
9a-9b=27
a-b=3
a+b=9
a-b=3
2a=12
a=6 czyli b=3
liczba I 63
liczba II 36
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