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i 1+1=2 czyli suma ;D
x*y=-1
x=2-y
x*y=-1
(2-y)*y=-1
-y²+2y+1=0
y²-2y-1=0
Δ=4+4=8 √Δ=2√2
y1= (2+2√2)/2= 1+√2 x+1+√2=2 x=1-√2
y2=(2-2√2)/2=1-√2 x+1-√2=2 x=1+√2
zatem rozwiazenim sa liczby (1+√2) i (1-√2)