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<ABC = 2x°
<BCA = 3x°
<ABC = ?
<A + <B + <C = 180°
60° + 2x° + 3x° = 180°
5x° = 120°
x =24°
<ABC = 2x° = 2(24) = 48°
a + b + c = 180
60 + 2x + 3x = 180
5x = 180 - 60
5x = 120
x = 24
ABC = 2x
ABC = 2(24)
ABC = 48
Jadi, besar sudut ABC adalah 48 derajat.