Subuah balok berukuran panjang (5x+1)cm,lebar(3x-2)cm dan ttinggi (x+5) . edangkanjulah panjang rusuk-rusuknya 124 cm .hitung : A.nilai x b.luas permukaan balok c.volume
Avicennaa
Jumlah panjang rusuk = 4 (P + L + T) 124 = 4(5x+1) + (3x - 2) + ( x + 5) 124 / 4 = 9x + 4 31 = 9x + 4 31 -4 = 9x 27 = 9x x = 3
P = 5x + 1 =16 L = 3x - 2 = 7 T = x + 5 = 8
luas permukaan = 2 ( PL + PT + LT) \ = 2 ( 16.7 + 16.8 + 7.8) = 2 x 296 = 592
124 = 4(5x+1) + (3x - 2) + ( x + 5)
124 / 4 = 9x + 4
31 = 9x + 4
31 -4 = 9x
27 = 9x
x = 3
P = 5x + 1 =16
L = 3x - 2 = 7
T = x + 5 = 8
luas permukaan = 2 ( PL + PT + LT)
\ = 2 ( 16.7 + 16.8 + 7.8)
= 2 x 296
= 592
Volume = P x L x T
= 16 x 7 x 8
= 896