Reaktansi Kapasitif
Xc = 1/2πfC = 1/(2π.60. 106.10⁻⁶)
Xc = 25 Ω
Reaktansi Induktif
Xl = 2πfL = 2π.60. 26,5.10⁻³
Xl = 10 Ω
Impedansi
Z² = R² + ( Xl - Xc )²
Z² = 20² + ( 10 - 25 )²
Z² = 400 + 225
Z² = 625
Z = 25 Ω
Αrus yang mengalir
I = V/Z = 100/25 = 4 A
Tegangan di L
Vl = I. Xl
Vl = 4. 10 = 40 v
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Reaktansi Kapasitif
Xc = 1/2πfC = 1/(2π.60. 106.10⁻⁶)
Xc = 25 Ω
Reaktansi Induktif
Xl = 2πfL = 2π.60. 26,5.10⁻³
Xl = 10 Ω
Impedansi
Z² = R² + ( Xl - Xc )²
Z² = 20² + ( 10 - 25 )²
Z² = 400 + 225
Z² = 625
Z = 25 Ω
Αrus yang mengalir
I = V/Z = 100/25 = 4 A
Tegangan di L
Vl = I. Xl
Vl = 4. 10 = 40 v