IMPEDANSI
Z² = R² + (-Xc)²
Z² = 400² + (-200)²
Z² = 160000 + 40000
Z² = 200000
Z = 447,2 Ω
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Verified answer
IMPEDANSI
Z² = R² + (-Xc)²
Z² = 400² + (-200)²
Z² = 160000 + 40000
Z² = 200000
Z = 447,2 Ω