Suatu persegi panjang memiliki panjang (2x-1)cm dan lebar(x+1)cm.jika kelilingnya 60 cm,tentukan luas persegi panjang tersebut?
dnnyz07
Kell = 2(p+l) 60 = 2(2x-1+x+1) 60= 2(3x) 60 = 6x 10 = x
panjang = 2(10)-1 = 19 cm lebar = 10+1 = 11 cm
luas = p x l = 19 x 11 = 209 cm^2
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mursidulamin41
kel. persegi panjang = 2(p+l)
60 = 2(2x-1+x+1)
60= 2(3x)
60 = 6x
10 = x
panjang = 2(10)-1 = 19 cm
lebar = 10+1 = 11 cm
luas = p x l
= 19 x 11
= 209 cm^2
mursidulamin41
kel. persegi panjang = 2(p+l)
60 = 2(2x-1+x+1)
60= 2(3x)
60 = 6x
10 = x
p = 2(10)-1 = 19 cm
le = 10+1 = 11 cm
lu = p x l
= 19 x 11
= 209 cm^2
60 = 2(2x-1+x+1)
60= 2(3x)
60 = 6x
10 = x
panjang = 2(10)-1 = 19 cm
lebar = 10+1 = 11 cm
luas = p x l
= 19 x 11
= 209 cm^2
60 = 2(2x - 1 + x + 1)
60 = 2 * 3x
60 = 6x
10 = x
P = 2 * 10 - 1 = 19
L = 10 + 1 = 11
L = p * l
= 19 * 11
= 209 cm^2