Question

Suatu paku yang tingginya 3 cm terletak 8 cm di depan cermin cekung yang jarak fokusnya 10 cm. tinggi bayangan paku

Answer 1

H = 3cm
s = 8cm
f = 10cm
1/f = 1/s + 1/s'
1/10 = 1/8 + 1/s'
1/s' = 1/10 - 1/8
1/s' = 4/40 - 5/40
1/s' = -1/40
s' = -40cm
M = |s'/s|
M = 40/8
M = 5 kali
M = h'/h
5 = h'/3
h' = 15cm