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Tr₁ = 27⁰C = 300⁰K
η₂ = 80% = 0,8
ΔTt = ...................?
Penyelesaian :
* Mencari suhu tinggi mula-mula (Tt₁)
η = 1 - Tr/Tt
0,6 = 1 - 300/Tt
300/Tt = 1 - 0,6
300/Tt = 0,4
Tt = 300/0,4
Tt₁ = 750⁰K
* Mencari suhu tinggi akhir (Tt₂)
Tt₁ (1 - η₁) = Tt₂ (1 - η₂)
750 (1 - 0,6) = Tt₂ (1 - 0,8)
750 (0,4) = Tt₂ (0,2)
300 = Tt₂0,2
Tt₂ = 300/0,2
Tt₂ = 1500⁰K
* Mencari kenaikan suhu reservoir tingi (ΔTt)
ΔTt = Tt₂ - Tt₁
ΔTt = 1500 - 750
ΔTt = 750⁰K
Jadi, kenaikan suhu reservoir tinggi sebesar 750⁰K