Suatu larutan penyangga dibuat denggan mencampurkan 100 ml larutan CH3COOH 1 M dengan 50 ml larutan NaOH 1 M ( Ka CH3COOH = 1 x 10^-5 ) Jika ditambah 10 ml larutan NaOH 0,1 M . Berapakah Ph nya sekarang ?
egayoza
CH3COOH + NaOH ⇒ CH3COONa + H2O m 100 50 b 50 50 50 50 s 50 - 50 50
H^+ = Ka × (mol asam ÷ mol garam) = 10^-5 × (50 ÷ 50) = 10^-5 pH awal = 5
ditambah 10 mL larutan NaOH 0,1 M
CH3COOH + NaOH ⇒ CH3COONa + H2O m 50 1 50 50 b 1 1 1 1 s 49 - 49 49
H^+ = Ka × (mol asam ÷ mol garam) = 10^-5 × (49 ÷ 49) = 10^-5 pH akhir = 5
m 100 50
b 50 50 50 50
s 50 - 50 50
H^+ = Ka × (mol asam ÷ mol garam)
= 10^-5 × (50 ÷ 50)
= 10^-5
pH awal = 5
ditambah 10 mL larutan NaOH 0,1 M
CH3COOH + NaOH ⇒ CH3COONa + H2O
m 50 1 50 50
b 1 1 1 1
s 49 - 49 49
H^+ = Ka × (mol asam ÷ mol garam)
= 10^-5 × (49 ÷ 49)
= 10^-5
pH akhir = 5