Question

Suatu larutan natrium asetat ch3coona mempunyai ph= 10. jika ka asam asetat= 10pangkat-5, kemolaran larutan tersebut adalah....M

Answer 1

Ph CH3COONa = 10
poh = 14 - 10 = 4  maka  OH- = 10^-4
OH- = akar [(kw/ka) x M]
10^-4 = akar [(10^-14/10^-5) x M]
(10^-4)^2 = 10^-9 x M
(10^-8/10^-9) = M
M = 10 Molar