Materi : Bangun Ruang Sisi Lengkung
t = 3V/πr²
t = 6,6 dm³/( 22/7 )( 10² )
t = ( 6,6 dm³ × 7/22 )/100
t = ( 0,3 dm³ × 7 )/100
t = 2,1 dm³/100
t = 2.100 cm³/100 cm²
t = 21 cm { c. }
Semoga bisa membantu
[tex] \boxed{ \colorbox{navy}{ \sf{ \color{lightblue}{ Answer\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Materi : Bangun Ruang Sisi Lengkung
Tinggi Kerucut
t = 3V/πr²
t = 6,6 dm³/( 22/7 )( 10² )
t = ( 6,6 dm³ × 7/22 )/100
t = ( 0,3 dm³ × 7 )/100
t = 2,1 dm³/100
t = 2.100 cm³/100 cm²
t = 21 cm { c. }
Semoga bisa membantu
[tex] \boxed{ \colorbox{navy}{ \sf{ \color{lightblue}{ Answer\:by\: BLUEBRAXGEOMETRY}}}} [/tex]