Suatu kerucut mempunyai jari jari 4cm tinggi 3cm.tentukan a.luas alas b.panjang garis pelukis c.luas selimut d.luas permukaan
nurkholifah28
A) alas = π × r² alas = 3,14 × 16 cm alas = 50,24 cm²
1 votes Thanks 0
dhitanayla07
Diketahui = r = 4 cm & t = 3 cm a.) Luas alas = πr² La = 3,14 × 4² = 3,14 × 16 = 50,24 cm². b.) Panjang Garis Pelukis = s = √t²+r² PGP = √4²+3² = √16+9 = √25 = 5 cm c.) Luas Selimut Kerucut = πrs LSK = 3.14 × 4 × 5 = 3.14 × 20 = 62.8 cm² d.) Luas Permukaan Kerucut = πr (r+s) LPK = 3,14 × 4 ( 4+5) = 12,56 × 9 = 113,04 cm²
alas = π × r²
alas = 3,14 × 16 cm
alas = 50,24 cm²
a.) Luas alas = πr²
La = 3,14 × 4²
= 3,14 × 16 = 50,24 cm².
b.) Panjang Garis Pelukis = s = √t²+r²
PGP = √4²+3²
= √16+9
= √25 = 5 cm
c.) Luas Selimut Kerucut = πrs
LSK = 3.14 × 4 × 5
= 3.14 × 20
= 62.8 cm²
d.) Luas Permukaan Kerucut = πr (r+s)
LPK = 3,14 × 4 ( 4+5)
= 12,56 × 9
= 113,04 cm²