Suatu hotel punya kmar 60 dgn tipe I,II.III. Jmlh kmar I dan II 35 dan tipe II dan III 45. Hitunglh bnyak kmar tipe I.II.III
subebe
Tipe I = a tipe II = b tipe III = c a+ b +c = 60 a + b = 35 a = 35 - b b + c = 45 c = 45 - b a + b + c = 60 35 - b + b + 45 - b = 60 80 - b = 60 b = 20 a = 35 - 20 = 15 c = 45 - 20 = 25 jadi banyak tipe I = 15, tipe II = 20, tipe III = 25
tipe II = b
tipe III = c
a+ b +c = 60
a + b = 35
a = 35 - b
b + c = 45
c = 45 - b
a + b + c = 60
35 - b + b + 45 - b = 60
80 - b = 60
b = 20
a = 35 - 20 = 15
c = 45 - 20 = 25
jadi banyak tipe I = 15, tipe II = 20, tipe III = 25