Jawab:
Transformasi geometris
Dilatasi [ P(0,0) , k ] :
x' = k(x) --> x = 1/k (x')
y' = k(y) --> y = 1/k (y')
Penjelasan dengan langkah-langkah:
4x - y = 3 atau
y = 4x - 3 { D { 0,0 , k ] } --> bayangan y' = 4x' + 12
.
substitusikan x = 1/k (x') dan y = 1/k (y') ke y = 4x - 3
1/k (y') = 4 ( 1/k) (x') - 3 ..(kalikan k)
y' = 4 x' - 3k ---> y' = 4x ' + 12
maka
- 3 k = 12
k = 12/-3
k = - 4
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Jawab:
Transformasi geometris
Dilatasi [ P(0,0) , k ] :
x' = k(x) --> x = 1/k (x')
y' = k(y) --> y = 1/k (y')
Penjelasan dengan langkah-langkah:
4x - y = 3 atau
y = 4x - 3 { D { 0,0 , k ] } --> bayangan y' = 4x' + 12
.
substitusikan x = 1/k (x') dan y = 1/k (y') ke y = 4x - 3
1/k (y') = 4 ( 1/k) (x') - 3 ..(kalikan k)
y' = 4 x' - 3k ---> y' = 4x ' + 12
maka
- 3 k = 12
k = 12/-3
k = - 4