Question

Suatu fungsi f(x) = ax+b .jika f(-2) = 13 dan f(3) = -7,maka nilai dari f(4) adalah ?

Answer 1

F(-2)=13
(-2)a+b=13
f(3)=-7
3a+b=-7
Kemudian eliminasi -2a+b=13
                              3a+b=- 7 -
                              -5a=20 --> a=-4
(-2)a+b=13 --> (-2)(-4)+b=13 --> 8+b=13
b=13-8 --> b=5
f(4)=(-4).4+5= -16+5 = -11

Answer 2

F(-2)=-2a+b = 13
f(3) = 3a+b = -7
eliminasi
-5a = 20
a = -4
substitusi
-2a+b = 13
-2(-4)+b = 13
8 + b = 13
b = 5
=> ax+b = -4x + 5
f(4)= -4(4) + 5 = -16+5 = -11

semoga bermanfaat :)