September 2018 1 11 Report

Matematyka z plusem, kl. II gim., zad. 17/str.52

e)\sqrt{3,5} * 2\sqrt{\frac{7}{8}}-\frac{3\sqrt[3]{0,02}}{\sqrt[3]{0,16}}=

f)\frac{\sqrt{0,8}:\sqrt{0,008}}{(-0,1)^{2}}+\frac{\sqrt[3]{0,1}}{\sqrt[3]{2,7}}

Pomóżcie, proszę!


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