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II liczba 4x
(3x)²+(4x)²=100
9x²+16x²=100
25x²=100
x²=100/25
x²=4
x=2
sprawdzenie
3*2=6 6²=36
4*2=8 8²=64
64+36=100
te liczby to 6 i 8.
(3x)²+(4x)²=100
9x²+16x²=100
25x²=100
x²=100/25
x²=4
x=2 v x=-2
więc 6 i 8 lub -6 i -8
a^2+b^2=100
3b=4a
a=3/4 b
9/16 b^2+b^2=100
25/16 b^2=100
b^2=100* 16/25
b^2=64
b= 8 lub b=-8
a= 3/4 * 8=6 lub a= 3/4*(-8)=-6