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2xy-4x+3 - 2xy +4x - 3=
=0
b) (-5x² +2xy² -3x )+(2xy² -3xy² + 2y )=
=-5x²+xy² -3x+ 2y
c) (-4ab² - 3ab + 4a - 5 )+( 3ab²+ 3ab -7a-3)=
= -ab² -3a -8
b) (-5x ( do potegi 2 ) +2xy (do potegi 2 ) -3x )+(2xy(do potegi 2 ) -3xy(do potegi drugiej + 2y )= nie moge tego rozczytac
c) (-4ab ( do potegi 2 ) - 3ab + 4a - 5 )+( 3ab ( do potegi 2 )+ 3ab -7a-3)=-4ab ( do potegi 2 ) - 3ab + 4a - 5 +3ab ( do potegi 2 )+ 3ab-7a-3=-8-1ab( do potegi 2 ) - 3a