Question

Sprowadź do najprostszej postaci (3a²b³)² ·(3a²b)³÷(3a²b²)⁴ i oblicz jego wartość dla a=-√2 i b=-2√5

Daję naj

Answer 1

(3a^2*b^3)^2 *(3a^2*b)^3/(3a^2*b^2)^4 = 

=3a^2 *a^4*b^6 *3^3 ^a^6 *b^3/3^4 *a^8*b^8 =

= 3^5 *a^10*b^9/3^4*a^8*b^8 = 3a^2b 

 

dla a = -V2i b = -2V5

3a^2b = 3*(-V2)^2 *(-2V5) = 3*2*(-2V5) = -12V5