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f)
L=cosα/sinα+sinα/(1+cosα)=
\frac{cos \alpha (1+cos \alpha )}{sin \alpha (1+cos \alpha )} + \frac{sin^2 \alpha }{sin \alpha (1+cos \alpha )} = \frac{cos \alpha +cos^2 \alpha +sin^2 \alpha }{sin \alpha (1+cos \alpha )} = \frac{1+cos \alpha }{sin \alpha (1+cos \alpha )} = \frac{1}{sin \alpha } [/tex]=P