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b=3√2 trzeba oszacowac √2 =1,41 b≈4,23
c=7-√3 oszacowac √3 =1,73 c≈5,27
a+b>c 6+4,23>5,27
a+c>b 6+5,27>4,23
b+c>a 4,23+5,27>6
a wiec moze miec takie dlugosci bokow