Sprawdź czy prawdziwa jest równość:
a) √27 + 3√48 - 3√75 = 0
b) √48 + √12 = √50
c) (7√12 - √48) * √75 = 150
d)(√24 - √150 + √54) : √12 = 0
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rozwiązanie w załączniku
a)
V27+3V48-3V75 = 0
L =V9*3 +3V16*3 -3V25*3 =3V3+12V3-15V3 = 0
P = 0
L = P
=====
b)
V48+V12 =V50
L =V16*3 +V483 =4V3+2V3 =6V3
P =V50 =V25*2 =5V2
L =I= P
=======
c)
(7V12-V48)*V75 =150
L =(7*V4*3 -V16*3) *V25*3 =(14V3-4V3)* 5V3 =70*3 -20*3 =210-60 = 150
P =150
L = P
=====
d)
(V24-V150+V54):V12 = 0
L =(V4*6 -V25*6 +V9*6):V12 =(5V6-5V6):V12 = 0:V12 = 0
P = 0
L = P
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