Question

Ptak o masie 0.5 kg leci na wysokości 100 m z predkoscia o wartosci 10 m/s.oblicz jego całkowita energie mechaniczna .

Answer 1

Ep = mgh
Ep = 0,5kg*10m/s²*100m
Ep = 5N*100m
Ep = 500J

Ek = mV²/2
Ek = (0,5kg*10m/s*10m/s)/2
Ek = [(5*10)/2]J
Ek = (50/2)J
Ek = 25J

Em = Ep+Ek
Em = 500J+25J
Em = 525J

Answer 2

Ep = mgh
Ep = 0,5 * 10 * 100
Ep = 500

Ek = mv2/2
Ek = 0,5 * (10)2/2
Ek = 0,5 * 100/2
Ek = 25

Emech = Ek + Ep
Emech = 25 + 500 = 525 J

Answer 3

E=mgh+mv^2/2
E=m(gh+v^2/2)
E=0,5(10*100+10^2/2)=525J