Lp1 = 2(pl + pt + lt)
= 2(10 × 10 + 10 × 20 + 10 × 20)
= 2(100 + 200 + 200)
= 2(500 cm²)
= 1.000 cm²
Lp2 = 5s²
= 5 × 12 × 12
= 5 × 144 cm²
= 720 cm²
LpT = Lp1 + Lp2
= 1.000 + 720
= 1.720 cm²
••••••••••••••••••••••••••••
Mapel : Matematika
Kelas : 6
Bab : Gabungan luas permukaan
~Solved By Noellmantap~
Jawab:
Penjelasan dengan langkah-langkah:
" Life is not a problem to be solved but a reality to be experienced! "
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Lp1 = 2(pl + pt + lt)
= 2(10 × 10 + 10 × 20 + 10 × 20)
= 2(100 + 200 + 200)
= 2(500 cm²)
= 1.000 cm²
Lp2 = 5s²
= 5 × 12 × 12
= 5 × 144 cm²
= 720 cm²
LpT = Lp1 + Lp2
= 1.000 + 720
= 1.720 cm²
••••••••••••••••••••••••••••
Mapel : Matematika
Kelas : 6
Bab : Gabungan luas permukaan
••••••••••••••••••••••••••••
~Solved By Noellmantap~
Jawab:
Penjelasan dengan langkah-langkah: