Jawaban:
no. 17. B
no. 18. B....titik B'' seharusnya (3, 2)
Penjelasan dengan langkah-langkah:
no.17
bayangan titik (x, y) di didalatasikan terhadap pusat (a, b) dgn skala k
maka :
x′ = a + k(x - a)
y' = b + k(y - b)
titik M(2, -4) di dilatasi oleh pusat P (-1, 2) dgn skala 3 maka M'
x' = -1 + 3(2 -(-1) = -1 + 9 = 8
y′ = 2 + 3(-4 -2) = 2 - 18 = -16
jadi M' = (8, - 16)
titik M' direfleksikan terhadap garis x = -2
titik P (x, y) direfleksikan ke garis x = h
P' = [(2h - x) , y]
M'' = [2(-2) - 8), -16]
M'' = (-12, -16).........(jawaban B)
.
no.18
bayangan titik P(x, y) di translasi T (h , k)
P' = [(x + h), (y + k)
titik A (4, -5), B (0, 0), C (-3, -2) ditranslasikan T (-2, 3) maka :
A' = [(4 - 2), (-5 + 3)]
A' = (2, -2)
B' = [(0 - 2), (0 + 3)]
B' = (-2, 3)
C' = [(-3 -2), (-2 + 3)]
C' = (-5, 1)
titik A (x, y) dirotasikan terhadap titik O (0, 0) sejauh 270º berlawanan arah jarum jam
maka A' = (y, -x)
A' = (2, -2)........A'' = (-2, -2)
B' = (-2, 3)........B'' = (3, 2)
C' = (-5, 1)........C'' = (1, 5)
jawaban (B)
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Jawaban:
no. 17. B
no. 18. B....titik B'' seharusnya (3, 2)
Penjelasan dengan langkah-langkah:
no.17
bayangan titik (x, y) di didalatasikan terhadap pusat (a, b) dgn skala k
maka :
x′ = a + k(x - a)
y' = b + k(y - b)
titik M(2, -4) di dilatasi oleh pusat P (-1, 2) dgn skala 3 maka M'
x' = -1 + 3(2 -(-1) = -1 + 9 = 8
y′ = 2 + 3(-4 -2) = 2 - 18 = -16
jadi M' = (8, - 16)
titik M' direfleksikan terhadap garis x = -2
titik P (x, y) direfleksikan ke garis x = h
P' = [(2h - x) , y]
M'' = [2(-2) - 8), -16]
M'' = (-12, -16).........(jawaban B)
.
no.18
bayangan titik P(x, y) di translasi T (h , k)
P' = [(x + h), (y + k)
titik A (4, -5), B (0, 0), C (-3, -2) ditranslasikan T (-2, 3) maka :
A' = [(4 - 2), (-5 + 3)]
A' = (2, -2)
B' = [(0 - 2), (0 + 3)]
B' = (-2, 3)
C' = [(-3 -2), (-2 + 3)]
C' = (-5, 1)
titik A (x, y) dirotasikan terhadap titik O (0, 0) sejauh 270º berlawanan arah jarum jam
maka A' = (y, -x)
A' = (2, -2)........A'' = (-2, -2)
B' = (-2, 3)........B'' = (3, 2)
C' = (-5, 1)........C'' = (1, 5)
jawaban (B)