khominghoo
27. r = 6% = 0,06 per semester M¹ = tabungan awal M² = tabungan akhir 1 tahun = 2 semester n = 20 tahun = 2 x 20 = 40 semester M² = M¹ x ( 1 + r )^n 11.828.575,63 = M¹ x (1+0,06)^40 11.828.575,63 = M¹ x 1,06^40 M¹ = 11.828.575,63/1,06^40 = 11.828.575,63/10,28571794 = Rp. 1.150.000,oo jawaban : b
M¹ = tabungan awal
M² = tabungan akhir
1 tahun = 2 semester
n = 20 tahun = 2 x 20 = 40 semester
M² = M¹ x ( 1 + r )^n
11.828.575,63 = M¹ x (1+0,06)^40
11.828.575,63 = M¹ x 1,06^40
M¹ = 11.828.575,63/1,06^40
= 11.828.575,63/10,28571794 = Rp. 1.150.000,oo
jawaban : b