Question

Soal nomor 1 & 2 dengan cara!

Answer 1

[1]
∑ I = ∑ m.r²
∑ I = [2][0,2]² + [3][0,3]²
∑ I = 0,08 + 0,27
∑ I = 0,35 kg.m²

[2]
∑ Fx = 0
T₂.cos 30° - T₁.cos 60° = 0
T₂.cos 30° = T₁.cos 60°
½√3.T₂ = ½.T₁
T₁ = T₂.√3 . . . (Persamaan-1)

∑ Fy = 0
T₂.sin 30° + T₁.sin 60° - w = 0
½.T₂ + ½√3.T₁ = 200
T₂ + √3.T₁ = 400 . . . . (Persamaan-2)

Substitusikan Persamaan-1 ke Persamaan-2

T₂ + √3.(T₂.√3) = 400
4T₂ = 400
∴ T₂ = 100 N
∴ T₁ = 100√3 N