" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
4 = D
b² - 4ac = 4
4a² - 4(1)(19 + a) = 4
4a² - 4a - 80 = 0
a² - a - 20 = 0
(a + 4)(a - 5) = 0
a = -4 ⇒ 30 + a - a² = 30 - 4 + 16 = 42
a = 5 ⇒ 30 + a - a² = 30 + 5 - 25 = 10
2) Cek diskriminan pembilang
D = 4a² - 4(-1)(-6)
= 4a² - 24
nilai a berkisar 1 < a < 2
maka diskriminan bernilai negatif
maka agar terpenuhi haruslah
x² + 3x > 0
x(x + 3) > 0
-3 < x < 0