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Verified answer
Kelas 9 MatematikaBab Akar dan Pangkat
BC = √(AB² + AC²)
BC = √((2√5 - √2)² + (√5 + 2√2)²)
BC = √(20 - 4√10 + 2 + 5 + 4√10 + 8)
BC = √35 cm
Verified answer
Triple pythagorasBC² = AB² + AC²
BC² = (2√5 - √2)² + (√5 + 2√2)²
BC² = (20 - 4√10 + 2) + (5 + 4√10 + 8)
BC² = 22 - 4√10 + 4√10 + 13
BC² = 35
BC = √35
JAWABAN B