Question

Soal Matematika terakhir:
Terimakasih..

Answer 1

[ Persamaan Garis Singgung ]

y = x³ - 2 // 1/2 x +6y = 6

1/2x - 6y = 6

Ralat Soal , jika Koef x dan y bernilai positif , maka x = i karena diferensial fungsi berbentuk sqrt

Gradien (m) = -koef x / koef y
Gradien (m) = -(1/2) / (-6)
Gradien (m) = 1/12

m = f'(x)
1/12 = 3x²
x² = 1/36
x = 1/6

y(x) = (1/6)³ - 2
y(x) = 1/216 - 2
y(x) = -431/216

Maka Titik Singgung Persamaan di ( 1/6 , -431 / 216)

PGS :
y - b = m(x - a)
y + 431/216 = 1/12 (x - 1/6)
216y + 431 = 18x - 3
18x - 216y - 428 = 0

~~~

DiferensiaL

f(x) = x³ + 3x² - 9x + 12
f'(x) < 0
3x² + 6x - 9 < 0
x² + 2x - 3 < 0
(x + 3)(x - 1) < 0

TikFung = { -3 , 1 }

x = -3
f(-3) = (-3)³ + 3(-3)² - 9(-3) + 12
f(-3) = -27 + 27 + 27 + 12
f(-3) = 39

x = 1
f(1) = 1³ + 3(1)² - 9(1) + 12
f(1) = 1 + 3 - 9 + 12
f(1) = 7

Nilai Minimum = 7


Mapel : Matematika
Kelas : XI SMA - MIPA