Question

Soal Matematika Tentang Lim Jangan Asal Jawab Dengan Cara

Answer 1

1. Lim (x²-x-6)/(2x²-x-15)

= Lim ((x-3)(x+2))/(2x²-6x+5x-15)

= Lim ((x-3)(x+2))/(2x(x-3)+5(x-3))

= Lim ((x-3)(x+2))/((2x+5)(x-3))

= Lim (x+2)/(2x+5)

subtitusikan 3 ke x

= (3+2)/(2(3)+5)

= 5/(6+5)

= 5/11

2. Lim (√x-2)/(x-4)

= Lim (√x-2)/((√x-2)(√x+2))

= Lim 1/(√x+2)

subtitusikan 4 ke x

= 1/(√4+2)

= 1/(2+2)

= 1/4

3. Lim (2-√(4-x))/x

= Lim (2-√(4-x))/x. (2+√(4-x))/(2+√(4-x))

= Lim (4-(4-x))/(x(2+√(4-x)))

= Lim (4-4+x)/(x(2+√(4-x)))

= Lim x/(x(2+√(4-x)))

= Lim 1/(2+√(4-x))

subtitusikan 0 ke x

= 1/(2+√(4-0))

= 1/(2+√4)

= 1/(2+2)

= 1/4

4. Lim (2-√(x-3))/(x²-49)

= Lim (2-√(x-3))/(x²-49). (2+√(x-3))/(2+√(x-3))

= Lim (4-(x-3))/((x²-49)(2+√(x-3)))

= Lim (4-x+3)/((x-7)(x+7)(2+√(x-3)))

= Lim (7-x)/((x-7)(x+7)(2+√(x-3)))

= Lim -(x-7)/((x-7)(x+7)(2+√(x-3)))

= Lim -1/((x+7)(2+√(x-3)))

subtitusikan 7 ke x

= -1/((7+7)(2+√(7-3)))

= -1/(14(2+√4))

= -1/(14(2+2))

= -1/(14(4))

= -1/56

Mapel: Matematika

Kelas: 11

Materi: Limit

Answer 2

Penjelasan dengan langkah-langkah:

Mapel :Matematika

Kelas :11

Materi :Limit