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1.) y = 2/3x -6 misal x = 0 y = 0-6 y = -6 misal y=0 0 = 2/3x -6 6 = 2/3x x = 9 jadi koordinat nya (9,-6) gambarnya sesuai koordinat itu.
2.) x -3y +2 = 0 -3y = -x -2 3y = x +2 y = ⅓ x +2/3 m1 = ⅓
karena //, maka m1 = m2 y - y1 = m2(x - x1) y - 5 = ⅓ (x - (-2)) y - 5 = ⅓ (x +2) y - 5 = ⅓ x + ⅔ (dikalikan 3) 3y -15 = x + 2 -x +3y -17 = 0 x -3y +17 = 0
y = 2/3x -6
misal x = 0
y = 0-6
y = -6
misal y=0
0 = 2/3x -6
6 = 2/3x
x = 9
jadi koordinat nya (9,-6)
gambarnya sesuai koordinat itu.
2.)
x -3y +2 = 0
-3y = -x -2
3y = x +2
y = ⅓ x +2/3
m1 = ⅓
karena //, maka m1 = m2
y - y1 = m2(x - x1)
y - 5 = ⅓ (x - (-2))
y - 5 = ⅓ (x +2)
y - 5 = ⅓ x + ⅔ (dikalikan 3)
3y -15 = x + 2
-x +3y -17 = 0
x -3y +17 = 0
3.)
4y = -3x +5
y = -¾ x +5/4
m1 = -¾
karena tegak lurus maka :
m1 .m2 = -1
-¾ .m2 = -1
m2 = -1 : (-¾)
m2 = 4/3
y - y1 = m2(x -x1)
y -2 = 4/3 (x -(-1))
y -2 = 4/3 (x +1)
y -2 = 4/3 x +4/3. (dikalikan 3)
3y -6 = 4x +4
3y -4x -10 = 0
4.)ax+by = ab
-3x + 3y = -9
maap kalo salah
semoga membantu