Suatu kerucut padat V= 1232 cm kubik. jika t= 24 cm & phi= 22/7. hitunglah luas permukaan/sisi kerucut
5dregensleyer
Volum = 1/3 x π x r² x t 1232 = 1/3 x 22/7 x r² x 24 1232 = 22/7 x 8 x r² 1232 = 176/7 x r² 1232 x 7/167 = r² 7 x 7 = r² 49 = r² √49 = r 7 = r sisi miring krucut s = √ 7² + 24² = √ 49 + 576 = √625 = 25 cm luas permukaan Lp = ( π x r²) + ( π x r x s) = ( 22/7 x7 x7) + ( 22/7 x7 x 25) = ( 22 x 7 ) + ( 22 x 25) = 154 + 550 = 704 cm²
1232 = 1/3 x 22/7 x r² x 24
1232 = 22/7 x 8 x r²
1232 = 176/7 x r²
1232 x 7/167 = r²
7 x 7 = r²
49 = r²
√49 = r
7 = r
sisi miring krucut
s = √ 7² + 24²
= √ 49 + 576
= √625
= 25 cm
luas permukaan
Lp = ( π x r²) + ( π x r x s)
= ( 22/7 x7 x7) + ( 22/7 x7 x 25)
= ( 22 x 7 ) + ( 22 x 25)
= 154 + 550
= 704 cm²