6. Uzasadnij, że dla każdego kąta ostrego zachodzi związek:
(tgα + ctgα)²=1/sin²α·cos²α
(sinα/cosα+cosα/sinα)²=(sin²α/cosαsinα+cos²α/sinαcosα)²=((sin²α+cos²α)/sinαcosα)²=
=(1/sinαcosα)²=1²/(sinαcosα)²=1/sn²ααos²α
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(tgα + ctgα)²=1/sin²α·cos²α
(sinα/cosα+cosα/sinα)²=(sin²α/cosαsinα+cos²α/sinαcosα)²=((sin²α+cos²α)/sinαcosα)²=
=(1/sinαcosα)²=1²/(sinαcosα)²=1/sn²ααos²α