Question

Sin⁴A = ? plissss pake caranyaaaa

Answer 1

Berhubung soalny. ga jelas, ane bikin tambah sakit mata aja

sin^4 A = sin^2 (A) * sin^2(A)
= (1-cos^2 A)*(sin^2 A)
= sin^2 A - cos^2A sin^2A
= sin^2A - (cos A sin A)^2
= sin^2 A - (sin 2A/2)^2
= sin^2 A - (sin^2 2A / 4)

atau

(1-cos^2 A) - cos^2 A sin^2 A
= 1 - cos^2 A - cos ^2 A sin^2 A
= 1 - cos^2 A ( 1- sin^2 A)
= 1- cos^2 A * cos^2 A
= 1- cos^4 A

sekalian minta thanks dan brainliest answer

Answer 2

Sin⁴ A =  (sin² A)²
= (1/2 - 1/2 cos 2A)²
= 1/4 - 1/2 cos 2A + 1/4 cos² 2A
= 1/4 - 1/2 cos 2A + 1/4 ( 1/2 cos 4A  + 1/2)
= 1/4 - 1/2 cos 2A + 1/8 cos 4A + 1/8
= 1/8 cos 4A - 1/2 cos 2A + 3/8
= 1/8 ( cos 4A - 4 cos 2A + 3)
..