Question

Sin^15-sin^105 =
tolong ini gimana caranya?

Answer 1

Sin A - sin B = 2 cos [(A+B)/2] sin [(A-B)/2] Sin 15 - sin 105 = 2 cos [(15+105)/2] sin [(15-105)/2] = 2 cos 60 sin -45 = 2.1/2.-1/2akar2 = -1/2akar2