Udowodnij tożsamość : sin alfa=(1/sin alfa + ctg alfa) (1-cos alfa)
ps.dam maksa za rozwiązanie na dzisiaj lub jutro
P = [ 1/sin alfa + ctg alfa]*[ 1 - cos alfa] =
= [ 1/sin alfa + cos alfa/ sin alfa]*[ 1 - cos alfa] =
= [ ( 1 + cos alfa)/sin alfa ] * [ 1 - cos alfa] =
= ( 1 - cos ^2 alfa )/ sin alfa =
= sin^2 alfa / sin alfa = sin alfa = L
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P = [ 1/sin alfa + ctg alfa]*[ 1 - cos alfa] =
= [ 1/sin alfa + cos alfa/ sin alfa]*[ 1 - cos alfa] =
= [ ( 1 + cos alfa)/sin alfa ] * [ 1 - cos alfa] =
= ( 1 - cos ^2 alfa )/ sin alfa =
= sin^2 alfa / sin alfa = sin alfa = L