Question

Sin 1500 derajat + cos 2040 derajat - tan 3600 derajat=...

Answer 1

●Sin 1500 = sin(5×360+300)
=sin 300
sin300 = sin(360-60)
=sin60= -1/2 akar3
●cos 2040 = cos (6×360 + 120)
=cos 120
cos 120=cos (180-60)
=cos 60 = -1/2
●Tan 3600= tan (10×360+0)
=tan 0°
=0

=-1/2 akar 3 + (-1/2) - 0
=-1/2 akar 3 - 1/2