Silnik Carnota o sprawnośći 29% oddaje ciepło chłodnicy o tem t1=-10C. Oblicz temperature grzejnicy i podaj ja w stopniach Celcjusza
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dane:
η = 29% = 0,29
t2 = -10*C
T2 = (-10+273)K = 263 K - temperatura chłodnicy
szukane:
T1 = ?
T1 - T2
η = ------------ I*T1
T1
ηT1 = T1 - T2
ηT1 - T1 = -T2
T1 - ηT1 = T2
T1(1-η) = T2 /:(1-η)
T1 = T2/(1-η)
T1 = 263/(1-0,29) = 263/0,71
T1 = 370,42 K
t1 = (370,42 - 273)*C
t1 = 97,4 *C
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Odp. Temperatura grzewnicy wynosi 97,4 *C.