2[4(-y-3) - (2y+1)] = 10y-6
2[ -4y - 12 - 2y - 1] = 10y - 6
2[ -6y - 13 ] = 10y - 6
-12y - 26 = 10y - 6
- 26 + 6 = 10y + 12y
-20 = 22y
-20/22 = y
-10/11 = y
Eternamente axllxa
Respuesta:
Explicación paso a paso:
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2[4(-y-3) - (2y+1)] = 10y-6
2[ -4y - 12 - 2y - 1] = 10y - 6
2[ -6y - 13 ] = 10y - 6
-12y - 26 = 10y - 6
- 26 + 6 = 10y + 12y
-20 = 22y
-20/22 = y
-10/11 = y
Eternamente axllxa
Respuesta:
2[4(-y-3) - (2y+1)] = 10y-6
2[ -4y - 12 - 2y - 1] = 10y - 6
2[ -6y - 13 ] = 10y - 6
-12y - 26 = 10y - 6
- 26 + 6 = 10y + 12y
-20 = 22y
-20/22 = y
-10/11 = y
Explicación paso a paso: