Siemka, prosze o rozwiązanie tych działań jak najszybciej z góry dzięki ^^
- podane w załączniku
a)
(8k^2 -10)/2 -(20k^2 +15)/5) =
5(8k^2 -10) -2(20k^2 +15)=
=40k^2 -50- 40k^2 -30 =
= - 80
======
b)
(2x+3)^2 -(x-2)^2 =
= 4x^2 +12x+9 -(x^2 -4x+4) =
=4x^2 +12x+9 -x^2 +4x-4 =
=3x^2 +16x+5
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a)
(8k^2 -10)/2 -(20k^2 +15)/5) =
5(8k^2 -10) -2(20k^2 +15)=
=40k^2 -50- 40k^2 -30 =
= - 80
======
b)
(2x+3)^2 -(x-2)^2 =
= 4x^2 +12x+9 -(x^2 -4x+4) =
=4x^2 +12x+9 -x^2 +4x-4 =
=3x^2 +16x+5
=============