Question

siema potrzebuje to na wtorek legenda

^-to do kwadratu

2x-(2x-1)^=4x-(x+2)^-3x(x+1)

-4x-(3x-1)^-(4x+7)(4x-7)=2x-(5x+1)^

-2x-(x+1)^< ruwne 3x-(x-7)(x+7)

-6x-(6x-1)^=2x-(5x+2)^-11x(x+2)

-2x(7x+1)^ >równe 2x-(6x+2)^-(13x+2)(x-1)

2x-(6x-1)

Answer 1

a)

2x-(2x-1)²=4x-(x+2)²-3x(x+1)

2x –(4x² -4x +1) = 4x – ( x² + 4x + 4) – 3x² - 3x

2x – 4x² + 4x -1 = 4x - x² - 4x – 4 – 3x² -3x

2x – 4x² + 4x  - 4x + x² + 4x  + 3x² + 3x = -4 +1

9x = -3  /:9

x = -3/9

x = -1/3

 

b)

-4x-(3x-1)²-(4x+7)(4x-7)=2x-(5x+1)²

-4x –(9x² -6x +1) –(16x² -49) = 2x –( 25x² + 10x + 1)

-4x -9x² + 6x – 1 – 16x² + 49 = 2x – 25x² - 10x – 1

-4x -9x² + 6x  – 16x² - 2x + 25x² + 10x  = -1+1 - 49

10x = -49   /: 10

 x= -49/10

x = -4,9

 

c)

2x-(x+1)² ≤ 3x-(x-7)(x+7)

2x – ( x² + 2x + 1)≤ 3x – (x² - 49)

2x - x² - 2x -1 ≤ 3x - x² + 49

2x - x² - 2x  -  3x + x²  ≤  49 + 1

-3x ≤ 50    /:(-3)

x ≥ -50/3 

d)

-6x-(6x-1)² = 2x-(5x+2)²-11x(x+2)

-6x – ( 36x² -12x +1) = 2x – ( 25x² + 20x +4) – 11x² - 22x

-6x – 36x² + 12x – 1 = 2x – 25x² - 20x -4 – 11x² - 22x

-6x – 36x² + 12x - 2x + 25x² + 20x  + 11x² + 22x = -4 + 1

46x = -3   / : 46

x = - 3/46