Explicación:
V = 5 Lts
m He = 8 g
m N2 = 84 g
m H2O vapor de agua = 90 g H2O
T = 27º C + 273 = 300 ºK
Calcular :
a ) P=?
b) X , Pp =? C/u
Para resolver el ejercicio se aplica la siguiente fórmula de los gases P* V = n * R*T , de la siguiente manera :
nt = nHe + nN2 + nH2O v
nHe = 8 g He/ 4.003 g/mol = 2 mol
n N2 = 84 g/ 28 g/mol = 3 mol
n H2O = 90 g / 18 g/mol = 5 mol
nt = 2 mol +3 mol + 5 mol = 10 moles .
P * V = nt * R * T
P= nt * R * T /V = 10 moles * 0.0821 Lts *atm/ºK*mol * 300º K/ 5Lts
a) P = 49.26 atm .
b) XHe = 2 mol /10 mol = 0.2
X N2 = 3 mol / 10 mol = 0.3
X H2Ov = 5 mol / 10 mol = 0.5
Pp He = XHe *Pt = 0.2* 49.26 atm = 9.852 atm
Pp N2 = XN2 * Pt = 0.3* 49.26 atm = 14.778 atm
Pp H2O = XH2O* Pt = 0.5* 49.26 atm = 24.63 atm .
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Explicación:
V = 5 Lts
m He = 8 g
m N2 = 84 g
m H2O vapor de agua = 90 g H2O
T = 27º C + 273 = 300 ºK
Calcular :
a ) P=?
b) X , Pp =? C/u
Para resolver el ejercicio se aplica la siguiente fórmula de los gases P* V = n * R*T , de la siguiente manera :
nt = nHe + nN2 + nH2O v
nHe = 8 g He/ 4.003 g/mol = 2 mol
n N2 = 84 g/ 28 g/mol = 3 mol
n H2O = 90 g / 18 g/mol = 5 mol
nt = 2 mol +3 mol + 5 mol = 10 moles .
P * V = nt * R * T
P= nt * R * T /V = 10 moles * 0.0821 Lts *atm/ºK*mol * 300º K/ 5Lts
a) P = 49.26 atm .
b) XHe = 2 mol /10 mol = 0.2
X N2 = 3 mol / 10 mol = 0.3
X H2Ov = 5 mol / 10 mol = 0.5
Pp He = XHe *Pt = 0.2* 49.26 atm = 9.852 atm
Pp N2 = XN2 * Pt = 0.3* 49.26 atm = 14.778 atm
Pp H2O = XH2O* Pt = 0.5* 49.26 atm = 24.63 atm .